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SOLVED:How can you calculate the standard entropy change for a reaction from tables of standard entropies?

Calculate the standard enthalpy of reaction for the process:C6H6(l) 3 H2(g) –> C6H12(l)Given these standard enthalpies of combustion: C6H12(l) = -3919.86 kJ mol–1C6H6(l) = -3267.80 kJ mol–1H2(g) = -285.90 kJ mol–1C(s) = -393.50 kJ mol–1

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